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๐ฑ โ ๐ณ
[ํ๋ก๊ทธ๋๋จธ์ค] ํ๋ก์ธ์ค - python ๋ณธ๋ฌธ
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๋ฌธ์ ์ ๋ณด
https://school.programmers.co.kr/learn/courses/30/lessons/42587
ํ๋ก๊ทธ๋๋จธ์ค
์ฝ๋ ์ค์ฌ์ ๊ฐ๋ฐ์ ์ฑ์ฉ. ์คํ ๊ธฐ๋ฐ์ ํฌ์ง์ ๋งค์นญ. ํ๋ก๊ทธ๋๋จธ์ค์ ๊ฐ๋ฐ์ ๋ง์ถคํ ํ๋กํ์ ๋ฑ๋กํ๊ณ , ๋์ ๊ธฐ์ ๊ถํฉ์ด ์ ๋ง๋ ๊ธฐ์ ๋ค์ ๋งค์นญ ๋ฐ์ผ์ธ์.
programmers.co.kr
๋ฌธ์ ์ ํ : ํ
๋์ด๋ : level 2
์ฝ๋
(์ธ๋ฑ์ค, ๊ฐ) ์ด๋ ๊ฒ ํํ ๊ตฌ์กฐ๋ก ํ์ ๋ฃ์ด์ ํ์์
from collections import deque
def solution(priorities, location):
answer = 0
arr = []
q = deque([])
for i in range(len(priorities)):
q.append((i, priorities[i]))
while q:
v = q.popleft()
if len(q) == 0:
arr.append(v)
break
li = sorted(q, key = lambda x : x[1], reverse=True)
if v[1] >= li[0][1]:
arr.append(v)
else:
q.append(v)
for i in range(len(arr)):
if arr[i][0] == location:
answer = i+1
return answer
๋ค๋ฅธ ์ฌ๋ ํ์ด
def solution(priorities, location):
queue = [(i,p) for i,p in enumerate(priorities)]
answer = 0
while True:
cur = queue.pop(0)
if any(cur[1] < q[1] for q in queue):
queue.append(cur)
else:
answer += 1
if cur[0] == location:
return answer
python any(), all() : https://otugi.tistory.com/206
- any() : ํ๋๋ผ๋ True์ธ๊ฒ ์์ผ๋ฉด True
- all() : ๋ชจ๋ True์ฌ์ผ True ๋ฐํ
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'Algorithms' ์นดํ ๊ณ ๋ฆฌ์ ๋ค๋ฅธ ๊ธ
[ํ๋ก๊ทธ๋๋จธ์ค] ํผ๋ก๋ - python (0) | 2023.09.07 |
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[ํ๋ก๊ทธ๋๋จธ์ค] ๋์คํฌ ์ปจํธ๋กค๋ฌ - python (0) | 2023.08.31 |
[ํ๋ก๊ทธ๋๋จธ์ค] ์ ํ๋ฒํธ ๋ชฉ๋ก - python (0) | 2023.08.29 |
[ํ๋ก๊ทธ๋๋จธ์ค] ์์ ์ฐพ๊ธฐ - python (0) | 2023.08.25 |
[ํ๋ก๊ทธ๋๋จธ์ค] ๊ทค ๊ณ ๋ฅด๊ธฐ - Python (0) | 2023.08.15 |